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Grade 7 Math · Percent Increase and Decrease

Grade 7 Percent Increase and Decrease Practice Test

Build Grade 7 Math skills with five 10-question practice tests on percent change, increase and decrease multipliers, discounts, tax, salaries, populations, successive changes, and original values.

Percent Increase and Decrease Practice Tests

These Grade 7 Math practice tests help students calculate percent change and apply percentage multipliers. Students work with increases, decreases, discounts, tax, salaries, populations, original values, successive changes, and real-world price and budget situations.

Skills covered

  • Calculating percent increase and percent decrease from original and new values
  • Using increase multipliers such as 1.15 and decrease multipliers such as 0.80
  • Finding a new value after a percentage increase or decrease
  • Finding the original value from a final value and a percentage change
  • Applying discounts, sales tax, salary changes, population changes, and budgets
  • Analyzing successive percentage changes and explaining why they are not always additive

How to use these practice tests

Use the original amount as the denominator when calculating percent change. For an increase, multiply by (1+r); for a decrease, multiply by (1-r), where (r) is the decimal rate. For successive changes, apply each multiplier in order and keep the intermediate value before applying the next change.

For more Grade 7 Math practice, return to the Grade 7 Math category.

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Grade 7 Percent Increase and Decrease Practice Tests

A 10-question Grade 7 Math practice test on percent increase, percent decrease, multipliers, discounts, tax, salaries, populations, successive changes, and finding original values.

Identify the original value, calculate the change relative to that original, use increase or decrease multipliers, and check each result with estimation.

10 Questions
0/10 Questions0 %
Correct 0
Incorrect 0
Unanswered 10
1. QuestionMultiple choice

A value of 100 increases by 20%20\% and then decreases by 20%20\%. What is the final value?

Please select an answer first.

Correct answer: A

The correct answer is 9696.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: After the increase, the value is 120. Then decrease 120 by 20%: 120⋅0.80=96120\cdot0.80=96.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

After the increase, the value is 120. Then decrease 120 by 20%: 120⋅0.80=96120\cdot0.80=96.

2. QuestionMultiple choice

A value of 100 increases by 10%10\% twice. What is the final value?

Please select an answer first.

Correct answer: B

The correct answer is 121121.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: Apply the multiplier twice: 100⋅1.10⋅1.10=121100\cdot1.10\cdot1.10=121.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

Apply the multiplier twice: 100⋅1.10⋅1.10=121100\cdot1.10\cdot1.10=121.

3. QuestionMultiple choice

An $80 item receives a 25%25\% discount and then an 8%8\% tax on the sale price. What is the final cost?

Please select an answer first.

Correct answer: C

The correct answer is $64.80.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The sale price is 80⋅0.75=6080\cdot0.75=60. The taxed total is 60⋅1.08=64.8060\cdot1.08=64.80 dollars.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The sale price is 80⋅0.75=6080\cdot0.75=60. The taxed total is 60⋅1.08=64.8060\cdot1.08=64.80 dollars.

4. QuestionMultiple choice

A population of 800 increases by 12.5%12.5\% and then decreases by 10%10\%. What is the final population?

Please select an answer first.

Correct answer: D

The correct answer is 810810.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: After the increase: 800⋅1.125=900800\cdot1.125=900. After the decrease: 900⋅0.90=810900\cdot0.90=810.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

After the increase: 800⋅1.125=900800\cdot1.125=900. After the decrease: 900⋅0.90=810900\cdot0.90=810.

5. QuestionMultiple choice

A price changes from $200 to $230. What is the percent increase?

Please select an answer first.

Correct answer: A

The correct answer is 15%15\%.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The increase is $30, and 30÷200=0.15=15%30\div200=0.15=15\%.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The increase is $30, and 30÷200=0.15=15%30\div200=0.15=15\%.

6. QuestionMultiple choice

A number changes from 500 to 425. What is the percent decrease?

Please select an answer first.

Correct answer: B

The correct answer is 15%15\%.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The decrease is 75, and 75÷500=0.15=15%75\div500=0.15=15\%.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The decrease is 75, and 75÷500=0.15=15%75\div500=0.15=15\%.

7. QuestionMultiple choice

A $60 item is increased by 10%10\% and then discounted by 10%10\%. What is the final price?

Please select an answer first.

Correct answer: C

The correct answer is $59.40.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The intermediate price is $66. The final price is 66⋅0.90=59.4066\cdot0.90=59.40 dollars.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The intermediate price is $66. The final price is 66⋅0.90=59.4066\cdot0.90=59.40 dollars.

8. QuestionMultiple choice

A quantity is reduced by 50%50\% and then increased by 50%50\%. If it starts at 40, what is the result?

Please select an answer first.

Correct answer: D

The correct answer is 3030.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: After the reduction, the value is 20. Increasing 20 by 50% gives 20⋅1.5=3020\cdot1.5=30.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

After the reduction, the value is 20. Increasing 20 by 50% gives 20⋅1.5=3020\cdot1.5=30.

9. QuestionMultiple choice

A price changes from $150 to $180. What is the percent increase?

Please select an answer first.

Correct answer: A

The correct answer is 20%20\%.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The increase is $30, and 30÷150=0.20=20%30\div150=0.20=20\%.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The increase is $30, and 30÷150=0.20=20%30\div150=0.20=20\%.

10. QuestionMultiple choice

A number changes from 240 to 204. What is the percent decrease?

Please select an answer first.

Correct answer: B

The correct answer is 15%15\%.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The decrease is 36, and 36÷240=0.15=15%36\div240=0.15=15\%.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The decrease is 36, and 36÷240=0.15=15%36\div240=0.15=15\%.

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Frequently asked questions about Grade 7 Percent Increase and Decrease

What topics are covered?

The page covers percent increase, percent decrease, original and new values, multipliers, discounts, tax, salaries, populations, budgets, and successive percentage changes.

What value should be used for percent change?

Use the original value as the denominator: change divided by original, multiplied by 100 percent.

How many questions are on this page?

The page includes five mini tests with 10 questions each, for 50 Grade 7 Percent Increase and Decrease questions in total.