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Grade 7 Math · Percent Increase and Decrease

Grade 7 Percent Increase and Decrease Practice Test

Build Grade 7 Math skills with five 10-question practice tests on percent change, increase and decrease multipliers, discounts, tax, salaries, populations, successive changes, and original values.

Percent Increase and Decrease Practice Tests

These Grade 7 Math practice tests help students calculate percent change and apply percentage multipliers. Students work with increases, decreases, discounts, tax, salaries, populations, original values, successive changes, and real-world price and budget situations.

Skills covered

  • Calculating percent increase and percent decrease from original and new values
  • Using increase multipliers such as 1.15 and decrease multipliers such as 0.80
  • Finding a new value after a percentage increase or decrease
  • Finding the original value from a final value and a percentage change
  • Applying discounts, sales tax, salary changes, population changes, and budgets
  • Analyzing successive percentage changes and explaining why they are not always additive

How to use these practice tests

Use the original amount as the denominator when calculating percent change. For an increase, multiply by (1+r); for a decrease, multiply by (1-r), where (r) is the decimal rate. For successive changes, apply each multiplier in order and keep the intermediate value before applying the next change.

For more Grade 7 Math practice, return to the Grade 7 Math category.

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Grade 7 Percent Increase and Decrease Practice Tests

A 10-question Grade 7 Math practice test on percent increase, percent decrease, multipliers, discounts, tax, salaries, populations, successive changes, and finding original values.

Identify the original value, calculate the change relative to that original, use increase or decrease multipliers, and check each result with estimation.

10 Questions
0/10 Questions0 %
Correct 0
Incorrect 0
Unanswered 10
1. QuestionMultiple choice

What is the result of decreasing 150 by 20%20\%?

Please select an answer first.

Correct answer: A

The correct answer is 120120.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The decrease is 0.20⋅150=300.20\cdot150=30, so 150−30=120150-30=120.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The decrease is 0.20⋅150=300.20\cdot150=30, so 150−30=120150-30=120.

2. QuestionMultiple choice

What is the result of decreasing 80 by 12.5%12.5\%?

Please select an answer first.

Correct answer: B

The correct answer is 7070.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The decrease is 0.125⋅80=100.125\cdot80=10, so 80−10=7080-10=70.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The decrease is 0.125⋅80=100.125\cdot80=10, so 80−10=7080-10=70.

3. QuestionMultiple choice

What is the result of decreasing 64 by 25%25\%?

Please select an answer first.

Correct answer: C

The correct answer is 4848.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The decrease is 0.25⋅64=160.25\cdot64=16, so 64−16=4864-16=48.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The decrease is 0.25⋅64=160.25\cdot64=16, so 64−16=4864-16=48.

4. QuestionMultiple choice

What is the result of decreasing 500 by 8%8\%?

Please select an answer first.

Correct answer: D

The correct answer is 460460.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The decrease is 0.08⋅500=400.08\cdot500=40, so 500−40=460500-40=460.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The decrease is 0.08⋅500=400.08\cdot500=40, so 500−40=460500-40=460.

5. QuestionMultiple choice

What is the result of decreasing 72 by 10%10\%?

Please select an answer first.

Correct answer: A

The correct answer is 64.864.8.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The decrease is 0.10⋅72=7.20.10\cdot72=7.2, so 72−7.2=64.872-7.2=64.8.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The decrease is 0.10⋅72=7.20.10\cdot72=7.2, so 72−7.2=64.872-7.2=64.8.

6. QuestionMultiple choice

What is the result of decreasing 120 by 7.5%7.5\%?

Please select an answer first.

Correct answer: B

The correct answer is 111111.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The decrease is 0.075⋅120=90.075\cdot120=9, so 120−9=111120-9=111.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The decrease is 0.075⋅120=90.075\cdot120=9, so 120−9=111120-9=111.

7. QuestionMultiple choice

What is the result of decreasing 250 by 18%18\%?

Please select an answer first.

Correct answer: C

The correct answer is 205205.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The decrease is 0.18⋅250=450.18\cdot250=45, so 250−45=205250-45=205.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The decrease is 0.18⋅250=450.18\cdot250=45, so 250−45=205250-45=205.

8. QuestionMultiple choice

What is the result of decreasing 48 by 25%25\%?

Please select an answer first.

Correct answer: D

The correct answer is 3636.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The decrease is 0.25⋅48=120.25\cdot48=12, so 48−12=3648-12=36.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The decrease is 0.25⋅48=120.25\cdot48=12, so 48−12=3648-12=36.

9. QuestionMultiple choice

A number decreases by 30%30\% from 80. What is the new value?

Please select an answer first.

Correct answer: A

The correct answer is 5656.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The remaining amount is 70%70\% of 80: 0.70⋅80=560.70\cdot80=56.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The remaining amount is 70%70\% of 80: 0.70⋅80=560.70\cdot80=56.

10. QuestionMultiple choice

A value decreases by 20%20\% to become 96. What was the original value?

Please select an answer first.

Correct answer: B

The correct answer is 120120.

  1. Identify the original and new values: Determine which value is the original amount, which is the new amount, and whether the change is an increase or a decrease.
  2. Apply the percent relationship: The final value is 80%80\% of the original, so 96÷0.8=12096\div0.8=120.
  3. Check the result: Use the original value as the denominator for percent change and verify the direction and size of the change.

The final value is 80%80\% of the original, so 96÷0.8=12096\div0.8=120.

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Frequently asked questions about Grade 7 Percent Increase and Decrease

What topics are covered?

The page covers percent increase, percent decrease, original and new values, multipliers, discounts, tax, salaries, populations, budgets, and successive percentage changes.

What value should be used for percent change?

Use the original value as the denominator: change divided by original, multiplied by 100 percent.

How many questions are on this page?

The page includes five mini tests with 10 questions each, for 50 Grade 7 Percent Increase and Decrease questions in total.