Systems of Linear Equations Practice Tests

These Grade 8 Math practice tests cover graphing systems, intersections, substitution, elimination, equivalent systems, one solution, no solution, infinite solutions, and real-world models.

Skills covered

  • Solving systems by graphing, substitution, and elimination
  • Interpreting an ordered-pair intersection as the solution to both equations
  • Identifying parallel lines, the same line, one solution, no solution, and infinitely many solutions
  • Checking ordered pairs in both original equations
  • Modeling ticket sales, mixtures, rates, dimensions, coins, plans, and number relationships

How to use these practice tests

Choose a method that fits the system. After finding an ordered pair, substitute it into both equations and verify that the context makes sense.

For more Grade 8 Math practice, return to the Grade 8 Math category.

5. Test

Grade 8 Systems of Linear Equations Practice Tests

Practice Grade 8 Math questions about systems of linear equations, graphing, substitution, elimination, intersections, no solutions, infinite solutions, and applications.

Choose the best answer for each question. Check the ordered pair in both original equations and review the explanation after submitting your answers.

10 Questions
0/10 Questions0 %
Correct 0
Incorrect 0
Unanswered 10
1. QuestionMultiple choice

A movie theater sells adult tickets for $10 and student tickets for $6. Seven tickets cost $58. How many adult and student tickets were sold?

Please select an answer first.

Correct answer: A

The correct answer is 44 adult and 33 student tickets.

  1. Choose a system method: Use substitution, elimination, a graph, or an equivalent form that makes one variable easy to determine.
  2. Solve for the ordered pair: Use a+s=7a+s=7 and 10a+6s=5810a+6s=58. Substitution gives a=4a=4 and s=3s=3.
  3. Check both equations: Substitute the ordered pair into both original equations and verify that it satisfies each one.

Use a+s=7a+s=7 and 10a+6s=5810a+6s=58. Substitution gives a=4a=4 and s=3s=3.

2. QuestionMultiple choice

A farm has 10 chickens and rabbits. There are 28 legs total. How many rabbits are there?

Please select an answer first.

Correct answer: B

The correct answer is 44 rabbits.

  1. Choose a system method: Use substitution, elimination, a graph, or an equivalent form that makes one variable easy to determine.
  2. Solve for the ordered pair: Let r+c=10r+c=10 and 4r+2c=284r+2c=28. Substitution gives r=4r=4.
  3. Check both equations: Substitute the ordered pair into both original equations and verify that it satisfies each one.

Let r+c=10r+c=10 and 4r+2c=284r+2c=28. Substitution gives r=4r=4.

3. QuestionMultiple choice

A purchase includes some pens and notebooks. There are 8 items total and the total cost is $25. If a pen costs $2 and a notebook costs $5, how many notebooks were purchased?

Please select an answer first.

Correct answer: C

The correct answer is 33 notebooks.

  1. Choose a system method: Use substitution, elimination, a graph, or an equivalent form that makes one variable easy to determine.
  2. Solve for the ordered pair: Use p+n=8p+n=8 and 2p+5n=252p+5n=25. The solution is p=5p=5 pens and n=3n=3 notebooks.
  3. Check both equations: Substitute the ordered pair into both original equations and verify that it satisfies each one.

Use p+n=8p+n=8 and 2p+5n=252p+5n=25. The solution is p=5p=5 pens and n=3n=3 notebooks.

4. QuestionMultiple choice

A collection has 12 quarters and dimes worth $2.10. How many quarters are there?

Please select an answer first.

Correct answer: D

The correct answer is 66 quarters.

  1. Choose a system method: Use substitution, elimination, a graph, or an equivalent form that makes one variable easy to determine.
  2. Solve for the ordered pair: Use q+d=12q+d=12 and 0.25q+0.10d=2.100.25q+0.10d=2.10. The solution is q=6q=6 and d=6d=6.
  3. Check both equations: Substitute the ordered pair into both original equations and verify that it satisfies each one.

Use q+d=12q+d=12 and 0.25q+0.10d=2.100.25q+0.10d=2.10. The solution is q=6q=6 and d=6d=6.

5. QuestionMultiple choice

A traveler spends 6 hours walking at 3 mph and biking at 8 mph for 33 miles total. How many hours were spent biking?

Please select an answer first.

Correct answer: A

The correct answer is 33 hours.

  1. Choose a system method: Use substitution, elimination, a graph, or an equivalent form that makes one variable easy to determine.
  2. Solve for the ordered pair: Use w+b=6w+b=6 and 3w+8b=333w+8b=33. Solving gives b=3b=3 and w=3w=3.
  3. Check both equations: Substitute the ordered pair into both original equations and verify that it satisfies each one.

Use w+b=6w+b=6 and 3w+8b=333w+8b=33. Solving gives b=3b=3 and w=3w=3.

6. QuestionMultiple choice

A rectangle has perimeter 34 feet. Its length is 5 feet greater than its width. What are the dimensions?

Please select an answer first.

Correct answer: B

The correct answer is 1111 feet by 66 feet.

  1. Choose a system method: Use substitution, elimination, a graph, or an equivalent form that makes one variable easy to determine.
  2. Solve for the ordered pair: Use l=w+5l=w+5 and 2l+2w=342l+2w=34. The solution is w=6w=6 and l=11l=11.
  3. Check both equations: Substitute the ordered pair into both original equations and verify that it satisfies each one.

Use l=w+5l=w+5 and 2l+2w=342l+2w=34. The solution is w=6w=6 and l=11l=11.

7. QuestionMultiple choice

An event sells adult tickets for $12 and student tickets for $7. Nine tickets bring in $83. How many adult tickets were sold?

Please select an answer first.

Correct answer: C

The correct answer is 44 adult tickets.

  1. Choose a system method: Use substitution, elimination, a graph, or an equivalent form that makes one variable easy to determine.
  2. Solve for the ordered pair: Use a+s=9a+s=9 and 12a+7s=8312a+7s=83. Substitution gives a=4a=4 and s=5s=5.
  3. Check both equations: Substitute the ordered pair into both original equations and verify that it satisfies each one.

Use a+s=9a+s=9 and 12a+7s=8312a+7s=83. Substitution gives a=4a=4 and s=5s=5.

8. QuestionMultiple choice

Plan A costs $20 plus $0.05 per message. Plan B costs $35 plus $0.02 per message. At how many messages are the costs equal?

Please select an answer first.

Correct answer: D

The correct answer is 500500 messages.

  1. Choose a system method: Use substitution, elimination, a graph, or an equivalent form that makes one variable easy to determine.
  2. Solve for the ordered pair: Set the costs equal: 20+0.05m=35+0.02m20+0.05m=35+0.02m. Then 0.03m=150.03m=15, so m=500m=500.
  3. Check both equations: Substitute the ordered pair into both original equations and verify that it satisfies each one.

Set the costs equal: 20+0.05m=35+0.02m20+0.05m=35+0.02m. Then 0.03m=150.03m=15, so m=500m=500.

9. QuestionMultiple choice

Two numbers have a sum of 18 and a difference of 4. What are the numbers?

Please select an answer first.

Correct answer: A

The correct answer is 1111 and 77.

  1. Choose a system method: Use substitution, elimination, a graph, or an equivalent form that makes one variable easy to determine.
  2. Solve for the ordered pair: Use x+y=18x+y=18 and x−y=4x-y=4. Adding gives 2x=222x=22, so the numbers are 11 and 7.
  3. Check both equations: Substitute the ordered pair into both original equations and verify that it satisfies each one.

Use x+y=18x+y=18 and x−y=4x-y=4. Adding gives 2x=222x=22, so the numbers are 11 and 7.

10. QuestionMultiple choice

Apples cost $2 per pound and oranges cost $3 per pound. A 10-pound purchase costs $24. How many pounds are apples?

Please select an answer first.

Correct answer: B

The correct answer is 66 pounds.

  1. Choose a system method: Use substitution, elimination, a graph, or an equivalent form that makes one variable easy to determine.
  2. Solve for the ordered pair: Use a+o=10a+o=10 and 2a+3o=242a+3o=24. Substitution gives a=6a=6 and o=4o=4.
  3. Check both equations: Substitute the ordered pair into both original equations and verify that it satisfies each one.

Use a+o=10a+o=10 and 2a+3o=242a+3o=24. Substitution gives a=6a=6 and o=4o=4.

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