Motion and Kinematics Practice Tests

These Grade 11 Science practice tests examine position, displacement, speed, velocity, acceleration, motion graphs, constant-acceleration equations, free fall, projectiles, vectors, circular motion, and experimental data.

Skills covered

  • Distinguishing position, distance, displacement, speed, velocity, and acceleration
  • Interpreting position-time, velocity-time, and acceleration-time graphs using slopes and areas
  • Applying constant-acceleration equations, free-fall models, and projectile components
  • Resolving vectors, using relative velocity, analyzing circular motion, and connecting period with frequency
  • Planning kinematics experiments, identifying variables, evaluating data, uncertainty, outliers, and model assumptions

How to use these practice tests

Choose a coordinate direction first. Write the known quantities with units, select the equation that matches the information, and check the sign and physical meaning of the result.

For more Grade 11 Science practice, return to the Grade 11 Science category.

2. Test

Grade 11 Motion and Kinematics Practice Tests

Practice Grade 11 Science questions about position, displacement, speed, velocity, acceleration, graphs, vectors, projectiles, circular motion, and experimental data.

Choose the best answer. Define the coordinate direction, select the correct kinematics relationship, track units, and interpret graphs and data carefully.

10 Questions
0/10 Questions0 %
Correct 0
Incorrect 0
Unanswered 10
1. QuestionMultiple choice

Which equation gives final velocity for constant acceleration?

Please select an answer first.

Correct answer: A

The correct answer is vf=vi+atv_f=v_i+at.

  1. Identify the motion model: Determine whether the problem describes position, displacement, velocity, acceleration, a graph, a vector, or a specified motion scenario.
  2. Apply the kinematics relationship: For constant acceleration, final velocity equals initial velocity plus acceleration times elapsed time.
  3. Check direction and units: The correct answer is vf=vi+atv_f=v_i+at.

For constant acceleration, final velocity equals initial velocity plus acceleration times elapsed time.

2. QuestionMultiple choice

Which equation gives displacement for constant acceleration?

Please select an answer first.

Correct answer: B

The correct answer is Δx=vit+12at2\Delta x=v_it+\frac{1}{2}at^2.

  1. Identify the motion model: Determine whether the problem describes position, displacement, velocity, acceleration, a graph, a vector, or a specified motion scenario.
  2. Apply the kinematics relationship: The constant-acceleration position relationship includes the initial-velocity term and the 12at2\frac{1}{2}at^2 term.
  3. Check direction and units: The correct answer is Δx=vit+12at2\Delta x=v_it+\frac{1}{2}at^2.

The constant-acceleration position relationship includes the initial-velocity term and the 12at2\frac{1}{2}at^2 term.

3. QuestionMultiple choice

A car starts from rest and accelerates at 2 m/s22\,\text{m/s}^2 for 5 s. What is its final speed?

Please select an answer first.

Correct answer: C

The correct answer is 10 m/s10\,\text{m/s}.

  1. Identify the motion model: Determine whether the problem describes position, displacement, velocity, acceleration, a graph, a vector, or a specified motion scenario.
  2. Apply the kinematics relationship: Using vf=vi+atv_f=v_i+at with vi=0v_i=0, vf=(2)(5)=10 m/sv_f=(2)(5)=10\,\text{m/s}.
  3. Check direction and units: The correct answer is 10 m/s10\,\text{m/s}.

Using vf=vi+atv_f=v_i+at with vi=0v_i=0, vf=(2)(5)=10 m/sv_f=(2)(5)=10\,\text{m/s}.

4. QuestionMultiple choice

A runner changes velocity from 4 m/s to 16 m/s in 3 s. What is the average acceleration?

Please select an answer first.

Correct answer: D

The correct answer is 4 m/s24\,\text{m/s}^2.

  1. Identify the motion model: Determine whether the problem describes position, displacement, velocity, acceleration, a graph, a vector, or a specified motion scenario.
  2. Apply the kinematics relationship: Acceleration is a=16−43=4 m/s2a=\frac{16-4}{3}=4\,\text{m/s}^2.
  3. Check direction and units: The correct answer is 4 m/s24\,\text{m/s}^2.

Acceleration is a=16−43=4 m/s2a=\frac{16-4}{3}=4\,\text{m/s}^2.

5. QuestionMultiple choice

Which equation does not explicitly require time for constant acceleration?

Please select an answer first.

Correct answer: A

The correct answer is vf2=vi2+2aΔxv_f^2=v_i^2+2a\Delta x.

  1. Identify the motion model: Determine whether the problem describes position, displacement, velocity, acceleration, a graph, a vector, or a specified motion scenario.
  2. Apply the kinematics relationship: The relationship vf2=vi2+2aΔxv_f^2=v_i^2+2a\Delta x connects velocity, acceleration, and displacement without time.
  3. Check direction and units: The correct answer is vf2=vi2+2aΔxv_f^2=v_i^2+2a\Delta x.

The relationship vf2=vi2+2aΔxv_f^2=v_i^2+2a\Delta x connects velocity, acceleration, and displacement without time.

6. QuestionMultiple choice

A cyclist travels 120 m in 10 s at constant speed. What is the speed?

Please select an answer first.

Correct answer: B

The correct answer is 12 m/s12\,\text{m/s}.

  1. Identify the motion model: Determine whether the problem describes position, displacement, velocity, acceleration, a graph, a vector, or a specified motion scenario.
  2. Apply the kinematics relationship: Average speed is distance divided by time: 120/10=12 m/s120/10=12\,\text{m/s}.
  3. Check direction and units: The correct answer is 12 m/s12\,\text{m/s}.

Average speed is distance divided by time: 120/10=12 m/s120/10=12\,\text{m/s}.

7. QuestionMultiple choice

What is the displacement during the first 4 s for an object starting from rest with a=3 m/s2a=3\,\text{m/s}^2?

Please select an answer first.

Correct answer: C

The correct answer is 24 m24\,\text{m}.

  1. Identify the motion model: Determine whether the problem describes position, displacement, velocity, acceleration, a graph, a vector, or a specified motion scenario.
  2. Apply the kinematics relationship: Using Δx=12at2\Delta x=\frac{1}{2}at^2, Δx=12(3)(42)=24 m\Delta x=\frac{1}{2}(3)(4^2)=24\,\text{m}.
  3. Check direction and units: The correct answer is 24 m24\,\text{m}.

Using Δx=12at2\Delta x=\frac{1}{2}at^2, Δx=12(3)(42)=24 m\Delta x=\frac{1}{2}(3)(4^2)=24\,\text{m}.

8. QuestionMultiple choice

If acceleration is opposite the direction of velocity, what happens to speed?

Please select an answer first.

Correct answer: D

The correct answer is Speed decreases.

  1. Identify the motion model: Determine whether the problem describes position, displacement, velocity, acceleration, a graph, a vector, or a specified motion scenario.
  2. Apply the kinematics relationship: Acceleration opposite velocity reduces the velocity magnitude until the object may stop or reverse direction.
  3. Check direction and units: The correct answer is Speed decreases.

Acceleration opposite velocity reduces the velocity magnitude until the object may stop or reverse direction.

9. QuestionMultiple choice

What is the average velocity of an object with displacement 30 m30\,\text{m} north in 6 s6\,\text{s}?

Please select an answer first.

Correct answer: A

The correct answer is 5 m/s5\,\text{m/s} north.

  1. Identify the motion model: Determine whether the problem describes position, displacement, velocity, acceleration, a graph, a vector, or a specified motion scenario.
  2. Apply the kinematics relationship: Average velocity is displacement divided by time: 30/6=5 m/s30/6=5\,\text{m/s} north.
  3. Check direction and units: The correct answer is 5 m/s5\,\text{m/s} north.

Average velocity is displacement divided by time: 30/6=5 m/s30/6=5\,\text{m/s} north.

10. QuestionMultiple choice

Why must a constant-acceleration equation use consistent units?

Please select an answer first.

Correct answer: B

The correct answer is Because the terms must represent compatible physical quantities.

  1. Identify the motion model: Determine whether the problem describes position, displacement, velocity, acceleration, a graph, a vector, or a specified motion scenario.
  2. Apply the kinematics relationship: Using meters, seconds, and meters per second keeps each term dimensionally consistent and prevents scale errors.
  3. Check direction and units: The correct answer is Because the terms must represent compatible physical quantities.

Using meters, seconds, and meters per second keeps each term dimensionally consistent and prevents scale errors.